A merchant has 3 kinds of wine. 117 litre of first kind, 130 litre of second kind & 143 litre of third kind. Find the least number of equal casks of equal size in which the wine can be stored without mixing.
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Answered by
1
u hav to find hcf of the no of wines
HCF of 117,130,143 = 13
now req no of casks = 117+130+143/13 = 30 :)
HCF of 117,130,143 = 13
now req no of casks = 117+130+143/13 = 30 :)
Answered by
14
Hello,
Wine 1 = 117 l
Wine 2 = 130 l
Wine 3 = 143 l
Now,
We need to find HCF to get the highest capacity of each container
So,
HCF (117,130,143) = 13
Now,
No. Of containers for wine 1 = 117/13 = 9
No of containers for wine 2 = 130/13 = 10
No. Of containers for wine 3 = 143/13 = 11
So,least number of containers = 10+11+9=30
Hope this will be helping you ✌️
Wine 1 = 117 l
Wine 2 = 130 l
Wine 3 = 143 l
Now,
We need to find HCF to get the highest capacity of each container
So,
HCF (117,130,143) = 13
Now,
No. Of containers for wine 1 = 117/13 = 9
No of containers for wine 2 = 130/13 = 10
No. Of containers for wine 3 = 143/13 = 11
So,least number of containers = 10+11+9=30
Hope this will be helping you ✌️
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