Math, asked by ajexconde032, 3 months ago

A merchant has twice as much money invested at 12% as he has at 10%. If his annual income from both investment us P 84,000, how much has he invested at each rate?

Answers

Answered by jagadeeswar790
3

Answer:

Let

x = represents the money invested at 10%

2x = represents the money invested at 12% (2 times as much as at 10%)

The total annual interest from both investments is $84,000:

0.10x + 0.12*(2x) = 84000

........

click here to see the equation solved for x

........

x = $247,058.82

2x = 2*247,058.82 = $494,117.64

The merchant invested $247,058.82 at 10% and $494,117.64 at 12%.

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