Math, asked by arawalgaonkar, 8 months ago

A merchant mixes three kinds of mangoes costing $120, $X, and $200 per kg in the ratio 1:4:2 so that the resultant mixture when sold at $198 per kg, yeilds a profit of 20%. What is the value of X?

Answers

Answered by Anonymous
3

Answer:

Answer: B) Rs. 49.2

Explanation:

Total cost of all varieties of mangoes = 20 x 2 + 40 x 3 + 50 x 5 = 40 + 120 + 250 = Rs. 410

Then, cost of 1 kg mangoes = 410/10 = Rs. 41

To get 20% profit,

The rate at which the mangoes should be sell = 120/100 x 41 = Rs. 49.2

Answered by Ashish132213
6

Step-by-step explanation:

  • (120 + 4X + 2×200) 120% = 7 × 198
  • (4X +520) 120/100 = 7 × 198
  • 4X + 520 = 7 ×198 × 10/12
  • 4X + 520 = 7 ×198 × 5/6
  • 4X + 520 = 35 × 33
  • 4X + 520 = 1155
  • 4X = 635
  • X = 158.75
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