Question

a merchant pays duty on certain goods at three different places.at the first place, he gives 1/3rd of the worth of goods, at the second place he gives 1/4th of the remaining amount and at the third place, he gives 1/5th of the remaining amount.If the total duty paid by him is RS.1020.what is the total worth of the goods? ​

Answer 1

Step-by-step explanation:

let total goods=60

60×1/3=20

remain 60-20=40

40×1/4=10

reamin=40-10=30

30×1/5=6

remain=30-6=24

20+10+6====1020

36===1020

1====1020/36

60===1020×60/36

=======1700₹