Question

A merchant sells one kind of rice at Rs. 10 per kg and loses 10% and another kind of rice at Rs. 20 per kg and gains
20%. He mixes them together in equal proportion and sells the mixture at Rs. 15 per kg. Then his gain % or loss % is​

Answer 1

Answer:

If Sin A = 3/4 find all t- ratios

Answer 2

Answer:

The gain percent  is 8 %.

Step-by-step explanation:

Given selling price of one kind of rice = Rs. 10 per kg

Loss percentage = 10%

Selling price another kind of rice at Rs. 20 per kg

Gain percentage = 20%

Selling price of the mixture = Rs. 15 per kg

In first kind or rice, selling price and loss % are given,

therefore the cost price = $100\times \frac{SP}{100-loss\%}$

$=100\times \frac{10}{100-10} =100\times \frac{10}{90} = \frac{100}{9}Rs.$

For second kind or rice, selling price and gain % are given,

therefore the cost price = $100\times \frac{SP}{100+gain\%}$

$=100\times \frac{20}{100+20} =100\times \frac{20}{120} = \frac{100}{6}Rs.$

If one kilogram from both the kind of rice is taken and mixed, then the cost price of the mixture is

$\frac{100}{9} +\frac{100}{6}$

$=\frac{200+300}{18} =\frac{500}{18} \approx27.78Rs$

The given selling price of the mixture = Rs. 15 per kg

For 2kg., the selling price of the mixture = $15\times 2=30Rs$

Selling price is more than the cost price, therefore there is gain.

And the gain % is

$=\frac{SP-CP}{CP} \times 100$

$=\frac{30-27.78}{27.78} \times 100=\frac{30-27.78}{27.78} \times 100$

$=7.99\approx8\%$

Hence, the gain percent  is 8 %.