Math, asked by royrupa089, 11 months ago

A merchant sells out sugar to a customer, using false weights and thereby gains 25 percent on his outlay. What weight does he substitute for one kg? Plz show working

Answers

Answered by RvChaudharY50
5

Solution :-

Let us assume that, the merchant use x gm less weight in place of 1 kg (1000gm) , and he gains 25% on his outlay .

then,

→ Weight Less used = x gm .

→ Actual weight used = (1000 - x) gm.

→ Gain = 25%

So,

→ (x * 100) / (1000 - x) = 25

→ 100x = 25(1000 - x)

→ 100x = 25000 - 25x

→ 100x + 25x = 25000

→ 125x = 25000

→ x = 200 gm.

Therefore,

→ Weight he substitute for one kg = (1000 - x) = 1000 - 200 = 800 gm (Ans.)

Learn more :-

Raju buys 3 goats for rs 11600. when he sells goats for 20 percent profit and sheep at 10 percent loss. he earns total p...

https://brainly.in/question/26745258

An item was sold at a profit of 12% after giving a discount of 12.5% on the list price. what would be the gain or loss p...

https://brainly.in/question/26616270

Answered by knjroopa
0

Step-by-step explanation:

Given A merchant sells out sugar to a customer, using false weights and thereby gains 25 percent on his outlay. What weight does he substitute for one kg? Plz show working

  •  Let the error is p gm. So we have
  •       Error / True weight – error x 100 = percentage profit
  •          p / 1000 – p x 100 = 25
  •             p / 1000 – p  = 25/100
  •            p / 1000 – p = ¼
  •          4p = 1000 – p
  •              5p = 1000
  •               Or p = 1000 / 5
  •               Or p = 200 gm
  • Therefore the weight used = 1000 – 200 = 800 gm

Reference link will be

https://brainly.in/question/1821492

Similar questions