Question

A merchant sells out sugar to a customer, using false weights and thereby gains 25 percent on his outlay. What weight does he substitute for one kg? Plz show working

Answer 1

Solution :-

Let us assume that, the merchant use x gm less weight in place of 1 kg (1000gm) , and he gains 25% on his outlay .

then,

→ Weight Less used = x gm .

→ Actual weight used = (1000 - x) gm.

→ Gain = 25%

So,

→ (x * 100) / (1000 - x) = 25

→ 100x = 25(1000 - x)

→ 100x = 25000 - 25x

→ 100x + 25x = 25000

→ 125x = 25000

→ x = 200 gm.

Therefore,

→ Weight he substitute for one kg = (1000 - x) = 1000 - 200 = 800 gm (Ans.)

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Answer 2

Step-by-step explanation:

Given A merchant sells out sugar to a customer, using false weights and thereby gains 25 percent on his outlay. What weight does he substitute for one kg? Plz show working

•  Let the error is p gm. So we have
•       Error / True weight – error x 100 = percentage profit
•          p / 1000 – p x 100 = 25
•             p / 1000 – p  = 25/100
•            p / 1000 – p = ¼
•          4p = 1000 – p
•              5p = 1000
•               Or p = 1000 / 5
•               Or p = 200 gm
• Therefore the weight used = 1000 – 200 = 800 gm

Reference link will be

https://brainly.in/question/1821492