Question

A merchant sells two dolls of price respectively ₹ 100 and ₹ 150 with a profit of 30% on first and a loss of 30% on second. What is his net profit/loss?

Answer 1

Cost price of 1st doll=100×(100÷130)=76.92
Cost price of 2nd doll=150×(100÷70)=214.28
Total Cp=214.28+76.92=291.20
Total Sell Price=100+150=250
Loss=291.20-250=41.20

Answer 2

Answer:

The merchant will face a net loss = Rs 41.20

Step-by-step explanation:

Selling Price of doll one = Rs. 100

Now, This was sold with profit of 30%

So, Cost Price of doll one = (100 × 100)/(100 + 30)

⇒ Cost Price of doll one = 10000/130

⇒ Cost Price of doll one = Rs. 76.92

Selling Price of doll second = Rs. 150

Now, This was sold with loss of 30%

So, Cost Price of doll one = (150 × 100)/(100 - 30)

⇒ Cost Price of doll one = 15000/70

⇒ Cost Price of doll one = Rs. 214.28

So, Total Cost Price of two dolls = 76.92 + 214.28

                                                      = Rs. 291.20

Total Selling Price of two dolls = 100 + 150

                                                   = Rs. 250

Therefore, The merchant will face a net loss = 291.2 - 250

                                                                             = Rs 41.20