Question

a merchant sells two models x and y of TV at ₹25000and ₹50000per set respectively .he gets profit of ₹150 on model x and ₹2000on model y​

Answer 1

Answer

Let number of desktop model be x and number of portable model be y

According to question,

Since, monthly demand doesn't exceed 250 units.

∴x+y≤250 ...(1)

Since, maximum invest is 70 lakhs.

∴25000x+40000y≤7000000⇒5x+8y≤1400 ...(2)

Also, quantity can't be negative.

∴x≥0,y≥0 ...(3)

We have to maximize profit Z

where Z=4500x+5000y

After plotting all the constraints given by equation (1),(2) and (3), we got the feasible region as shown in the image.

Corner points Value of Z=4500x+5000y

A(0,175) 875000

B(200,50) 1150000 (Maximum)

C(250,0) 112500

Hence, maximum profit that can be earned by the merchant will be 1150000 Rs

solution