Question

A merchant sold an item whose marked price is Rs 625 after giving a discount of 20%. But still he is managed to get profit of 25%. Then what is the cost price of the item?​
a) rs 550
b) rs 400
c) rs 575
d) rs 450

Answer 1

Given

• Marked price (MP) =Rs 625
• Discount % = 20%
• Profit % = 25%

To Find

• Cost Price

Formula Used

$\boxed{{\tt CP = MP \times \left(\dfrac{100 - D \% }{100 +P\% } \right)}}$

• On Substituting the Values

${ \sf \: \: \: \: \: : \: \implies CP = 625 \times \left(\dfrac{100 - 20}{100 + 25 } \right)}$

${ \sf \: \: \: \: \: : \: \implies CP = \cancel{625} {}^{5} \times \dfrac{80}{ \cancel{125}} }$

${ \sf \: \: \: \: \: : \: \implies CP = 5 \times 80 }$

${ \sf \: \: \: \: \: : \: \implies CP = ₹ 400 }$

Hance,

• cost price of the item is ₹ 400.

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More to know:-

• $\tiny\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin{array}{c | }\mathfrak {\bf OUR ~Formula} \\\hline\\ \\ 1. & \sf In~ Case ~ of ~ Profit \\ \\ & \sf SP =CP \times \dfrac{ (100- Profit\%)}{100} \\ \\ & \sf CP = \dfrac{100× SP}{100-Profit\%} \\ \\ \hline\\2. & \sf In~ Case ~ of ~Loss \\ \\ & \sf SP =CP \dfrac{ (100- Loss\%)}{100} \\ \\ & \sf CP = \dfrac{100× SP}{100-Loss\%} \\ \\ \hline \\3. & \sf Discount = M.P. – S.P.\\ \\ \hline \\ 4. & \sf Discount\% = \dfrac{Discount}{MP}×100\\ \\ \hline \\ 5. & \sf SP= MP× \left( \dfrac{100- Discount\%}{100}\right) \\ \\ \hline \\6. & \sf MP = \dfrac{100×SP}{100- Discount\%}\end{array}}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}$