Question

A merchant was carrying a load of three natural resources consisting of 105 coal bags, 140 iron rods, 175
oil cans, which has to be taken across a river. There is only one boat which will have to do many trips in
order to do so. The lazy boatman has his own conditions for transporting them. He insists that he will take
the same number of resources in every trip and they have to be of the same kind. He will naturally like to
take the largest possible number each time. Can you tell how many resources went in each trip?

Answer 1

Here, clearly we have to find the HCF of @
105,140,175.
You can do this by Euclid's division lemma or by prime factorisation method :-

Here we would use prime factorisation method:-

105=3*7*5
140=2*2*5*7
175=5*5*7

HCF=5*7=35

So the boatman will carry 35 animals of same type each time .....

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