Question

A mercury drop of radius 1.0 cm is sprayed into 1000000 droplets of equal size. Calculate the energy expanded.

Answer 1

we know that,

volume of one drop = volume of 1000 droplets

so,

(4/3)πR3 = 1000X (4/3)πr3

or

R3 = 1000 X r3

so,

r = R / 10

thus,

if R = 1mm = 10-3 m

then

r = 10-4 m

 

now, the surface energy is given as

E = T X A

or

E = 0.072 X 4πr2

 

so,

E = 0.8964 X 10-8 = 8.96 X 10-9 J/m2


hope it helps you

Answer 2

Answer:

Hear you go

Explanation:

Thank you

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