Question

a mercury drop of water has potential V on its surface.1000 such drops combine to form a new drop.find the potential on the surface of the new drop.​

Answer 1

Answer:

Explanation:

1000* Vsmall= V big

4/3πr³ *1000 = 4/3 π R³

r* 1000⅓ = R.. therefore 10r = R

Now, potential of small is V = Kq/ r

Potential of big V` = Kq/R , where R = 10r....V` = Kq/ 10r

V` = V/10 therefore potential at surface = V/ 10

Hope the answer is correct!!!

Answer 2

Answer:

100V.

Explanation:

This is good question for jee mains preparation.

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