A mercury thermometer records a temperature of 8 degrees Fahrenheit at 10 A.M. If the temperature drops by 3 degrees Fahrenheit every hour, what will be the temperature by 2 P.M. of the same day?
Answers
Answer:
The temperature by 2 P.M of the same day : -4°F
Further explanation
Temperature is used as a guide to the level of heat energy from objects
Temperature measures thermal energy
Temperature units include Celsius, Fahrenheit, Reaumur or Kelvin
We can calculate it in two ways
1. manual way
2. with the arithmetic series formula
1. manual
initial temperature = 8
Temperature drops by 3/hr
From 10 a.m to 2 pm , there is a difference of 4 hours
Then the final temperature
2. the arithmetic series
The arrangement of the numbers is like this:
a, a+d, a+2d, etc ,
so the temperature series :
8°F, 5°F, 2°F,...
a = initial term ⇒ initial temperature = 8° F
d = different (common difference) = -3°/hr
The formula for the nth term ⇒2 o'clock is the 5th hour(from 10 AM), so n = 5
Step-by-step explanation:
Answer:
The temperature by 2 P.M of the same day will be -4° F.
Step-by-step explanation:
Given: At 10 A.M, mercury thermometer records the temperature of 8° F.
After every hour, the temperature drops by 3° F.
To find: The temperature drops by 2 P.M of the same day.
At 10 A.M,
The temperature recorded = 8° F
After 1 hour, temperature drops by 3° F,
i.e., The temperature at 11 A.M = 8 - 3
= 5° F
At 12 noon,
The temperature again drops by 3° F = 5 - 3
= 2° F
At 1 P.M,
The temperature after dropping by 3° F = 2 - 3
= -1° F
Lastly, at 2 P.M,
The temperature would be = -1 - 3
= -4° F
Therefore, the temperature by 2 P.M of the same day will be -4° F.
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