Question

A merry-go-round is accelerated uniformly from
rest and attains an angular speed of 0.5 rad s in
the first 10s. If the net applied torque is 2000Nm,
calculate the moment of inertia of the merry-go-
round. What will the angular momentum of the
merry-go-round be after 20 s? Is the angular
momentum conserved ? Explain. ​

Answer 1

Explanation:

Since there is no external torque acting on the system, angular momentum is conserved.

Li=Lf

∴mvR+0=(I+mR2)ω where mvR is the angular momentum of the child wrt the center of the merry-go-round and angular momentum of the merry-go-round is zero initially since it is at rest.

ω=(I+mR2)mvR

u can use this formula to ca6