Question

a merry go round is rotating about a vertical axis at the rate of 60rev/min.Ifthe distance of a man from its axis is 2m ,his linear speed is ...

Answer 1

Given :

▪ Frequency of rotation = 60rev/min

▪ Radius of circular path = 2m

To Find :

▪ Linear speed of man.

SoluTion :

↗ Relation b/w linear speed and angular speed of an object moving in circular path is given by

✴ v = r × ω

where,

v denotes linear speed

r denotes radius of circular path

ω denotes angular speed

We know that, ω = 2π × f

where, f = frequency of rotation

↗ f = 60rev/min = 1rev/s

→ v = r × ω

→ v = r × (2π × f)

→ v = 2 × (2 × 3.14 × 1)

→ v = 4 × 3.14

→ v = 12.56 m/s

Answer 2

Answer:

The answer of this question is 4 pie