Physics, asked by sashu5061, 1 year ago

a merry go round rotates from rest with constant angular acceleration `α` . Ratio of time to rotate first 2 revolutions & next 2 revolutions is
1) 1:1
2) (√2+1):1
3) √2:1
4) 1:√2

Answers

Answered by gadakhsanket
215

Hey Dear,

◆ Answer - (2)

t1/t3 = √2+1

◆ Explanation -

Given that merry go round starts from rest. So ω0 = 0 rad/s.

For first two revolutions, θ = 2×2π rad

θ = ω.t1 + 1/2 α.t1^2

2×2π = 0×t1 + 1/2 × α × t1^2

t1^2 = 8π/α

t1 = √(8π/α)

For first four revolutions, θ = 4×2π rad

θ = ω.t2 + 1/2 α.t2^2

4×2π = 0×t2 + 1/2 × α × t2^2

t2^2 = 16π/α

t2 = √(16π/α)

Time taken for 3rd and 4th revolution is -

t3 = t2 - t1

t3 = √(16π/α) - √(8π/α)

t3 = (√2-1) √(8π/α)

Now, ratio of time to rotate first 2 revolutions and next 2 revolutions is -

t1/t3 = √(8π/α) / [(√2-1)√(8π/α)]

t1/t3 = 1/(√2-1) × (√2+1)/(√2+1)

t1/t3 = √2+1

Therefore, ratio of time to rotate first 2 revolutions & next 2 revolutions is √2+1.

Thanks dear...

Answered by debarpitadutta2001
17

Answer:

this attachment will help you to understand clearly

Explanation:

hope it helps you.

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