Question

A mess has food for 200 students for 35 days. If 50 new students join the

mess, then find the number of days for which the food shall last​

Answer 1

Answer:

let the provision day to be last now x

students at beginning 200

and provision 30 days

but 100 students join so obviously provision decrease so its inverse variation.

200×30=300×x

6000=300x

x=20

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Answer 2

Answer:

let the number of students be x

x×50=200×35

x=200×35÷50

x=20×7

x=140