Question

A message signal of frequency 10 KHz and peak voltage of 10V is used to modulate a carrier wave of frequency 1 MHz and peak voltage of 20V

Determine
1) Modulation index
2)the side band produced

Answer 1

1) given that Am = 10v and Ac = 20v

Modulation index is given by

µ = Am/Ac
plug in the values of Am and Ac ... we get
µ = 10/20 = 0.5

Where Am = Amplitude of modulated wave
Ac = Amplitude of Carrier wave

2) Side bands

The side bands are, (ωᴄ - ωm) and (ωc+ωm)
or we can write (fc - fm) and (fc + fm)

Where (ωᴄ - ωm) is the frequency of lower side band,
(ωc+ωm) is the frequency of upper side band .

also ωᴄ = carrier wave frequency
ωm = modulated wave frequency

∴ Frequency of lower side band = (ωᴄ - ωm)
= (1000-10)= 990 KHz

Frequency of upper side band = (ωᴄ + ωm)
= (1000+10)= 1010KHz

Answer 2

❤HOLA MATE❤

✍️ANSWER:-

given that Am = 10v and Ac = 20v

Modulation index is given by

µ = Am/Ac

plug in the values of Am and Ac ... we get

µ = 10/20 = 0.5

Where Am = Amplitude of modulated wave

Ac = Amplitude of Carrier wave

2) Side bands

The side bands are, (ωᴄ - ωm) and (ωc+ωm)

or we can write (fc - fm) and (fc + fm)

Where (ωᴄ - ωm) is the frequency of lower side band,

(ωc+ωm) is the frequency of upper side band .

also ωᴄ = carrier wave frequency

ωm = modulated wave frequency

∴ Frequency of lower side band = (ωᴄ - ωm)

= (1000-10)= 990 KHz

Frequency of upper side band = (ωᴄ + ωm)

= (1000+10)= 1010KHz

⭕HOPE IT HELPS⭕