Question

a metal alloy container 43% zinc and the rest is iron. Find the quantity of each metal in 2150g of this alloy.​

Answer 1

Step-by-step explanation:

2150÷100=21.5

21.5 ×43. (the amount of zinc )

= 924.5

now 43 -100 (the percent of iron )

= 57

now

21.5 ×57. (the amount of iron )

=1225.5

so the amount of zinc is 924.5 gram

amount of iron is 1225.5 gram

Answer 2

Step-by-step explanation:

Zinc=43/100*2150g=924.5g

Iron=57/100*2150g=1225.5g

Verification...924.5+1225.5=1250g