Question

A metal and another 63.94 percentage of metal. Show that these results are in accounting of with the law of multiple proportion

Answer 1

Answer:

This Law states that when two elements can combine to form more than one compound, the amounts of one of them that combines with a fixed amount of the other will exhibit a simple whole number relation.

If we assume we have 100 g of each, then the % = #g (convenience)

So the first one is 63.63 g metal : 36.37 g O (100 - 63.63 = 36.37)

and the second one is : 46.66 g metal : 53.34 g O

If we now divide g metal by g O in both cases, we get:

1.75 g metal: 1 g O

0.87 g metal: 1 g O

1.75/0.87 = exactly 2, so one oxide has exactly twice the amount (number of atoms) of metal as the other one does. so it's 2:1 metal atoms in the 2 oxides. So this illustrates the Law of Multiple Proportions.

Explanation:

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