Question

A metal ball immersed in alcohol weighs W, at 0°C and W,
at 59°C. The coefficient of cubical expansion of the metal is
less than that of alcohol. Assuming that the density of the
metal is large compared to that of alcohol, it can be shown
that
(a) W, >W2
(c) W <W2
(b) W = W2
(d) W = (W/2)​

Answer 1

Answer:

(c) W <W2 is the correct answer.

Explanation:

Given data:

A metal ball is immersed in alcohol at 0°C.

weight =W

Weight = W2 at 59°C

Coefficient of cubical expansion of the metal is less than that of alcohol.

Assume = the density of the

metal is large compared to that of alcohol,

Solution

The expansion of metal ball can be neglected as the coefficient of cubical expansion of the metal is less than that of alcohol which is given. The ball is put in the alcohol solution at 0°C.

Thus the alcohol gets displaced as the ball is immersed which is given by W.

We can consider w as the weight of ball

W=w (using Archemedis principle)

r is the density at 0°C

Density of alcohol at 50°C is greater than that at 0°C.

Thus W = rhg

Thus W is directly proportional to r

Hence, W<W2.

Thus, (c) W <W2 is the correct answer.