a metal ball of 2 kg is allowed to fall freely from rest from a height of 5 m above the ground. taking g=10m/s², calculate: (i) potential energy possessed by the ball when it's initially at rest (ii) kinetic energy of the ball just before it hits the ground.
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The velocity of the train v = 72 km/hr. The distance of the bridge is 1 km. = 1000 m. = 1100 m
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Answer:
Explanation:
here mass that is m=2kg and s that is h is -5m and g is alredy given
that is =10m/s
1) p.e=mgh
=2.(-10).(-5)
=100joule
2) k.e=1/2mv^2
=1/2.2.(0)^2= 1 JOULE
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