Question

A metal ball of 7 kg Falls from 12 meters
calculate:
potential energy of the ball before of the fall
potential energy possessed by a ball when it covered a distance of 5 meters during the fall
velocity of the ball when we discover 5 meters from the wall

Answer 1

Answer:

Given:

Mass of ball: 7 kg

Height: 12 m

To find:

▪Potential energy of the ball before the fall.

▪Potential energy possessed by the ball when it covered 5 m distance.

▪Velocity of the ball on 5 m from the wall.

Solution:

▪Potential energy before the fall:

m = 7 kg

g = 10 m/s^2

h = 0 m [before the fall]

Potential energy = mgh

=> P.E. = 7 × 10 × 0

=> Potential energy before fall = 0 J

▪ Potential energy on 5 m height:

m = 7 kg

g = 10 m/s^2

h = 5 m

Potential energy = mgh

=> P.E. = 7 × 10 × 5

=> Potential energy = 350 J

▪ Velocity of the ball:

m = 7 kg

h = 5 m

g = 10 m/s^2

Potential energy = Kinetic energy

=> mgh = 1/2 × mv^2

=> 10 × 5 = 1/2 × v^2

=> Velocity = 10 m/s

Hope it helps!!

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Answer 2

Explanation:

Hope it helps you.

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