Question

A metal ball of mass 2 kg moving with speed of 36 km/h has a head on collision with a stationary ball of mass 3 kg. If after collision both the balls move together find the loss in kinetic energy due to collision?

Answer 1

present kinetic energy is36×36

Answer 2

Answer:

The loss in the kinetic energy is 60 J.

Explanation:

Given;-

    Mass of 1st body , m₁ = 2kg

    Mass of 2nd body, m₂ = 3kg

    Velocity of 1st body , u₁= 36 km/h

                                          = 36 × 5/18 m/s

                                         = 10 m/s

    Velocity of 2nd body, u₂ = 0

   Relative Velocity, u = 10 m/s

Now, we know that since the two balls after collision are moving together, hence the case is of perfectly inelastic collision. And, we know that for a perfectly inelastic collision the loss in the kinetic energy is given by;

       Δ K.E. = 1/2 × (m₁m₂) × u²/ ( m₁ + m₂)

Putting the given values in the formula, we get;-

        Δ K.E. =  1/2 × 2 × 3 × 10²/ 2 + 3

        Δ K.E. =  300/5

     Δ K.E. = 60 J

Hope it helps! ;-))