Question

A metal ball of mass 5 kg falls from a height of 490 M how much time it will take to reach the ground ? (g=9.8 m/s2​

Answer 1

m=5kg

h=490m

u=0

a=9.8m/s2

S=ur+1/2at2

$490 = 1 \div 2 \times 9.8x {2}$

490=4.9x2

x2=490/4.9

t2=100

t=10sec

Answer 2

Hey mate, here is your answer :-

The ball will take 10 seconds to reach the ground.

Step - by - step explanation :-

Given :

$1 . \: h = s = 490 \: m \\ 2. \: g = 9.8 \: \frac{m}{ {s}^{2} } \\ \\ to \: find \: (t) = ....... \\ \\ solution \: \\ according \: to \: newtons \: second \: equation \: for \: free \: fall \\ s = \frac{1}{2} g {t}^{2} \\ 2s = g {t}^{2} \\ \frac{2s}{g} = {t}^{2} \\ \sqrt{ \frac{2s}{g} } = t \\ t = \sqrt{ \frac{2s}{g} } \\ t = \sqrt{ \frac{2 \times 490}{9.8} } \\ t = \sqrt{ \frac{2 \times 4900}{98 } } \\ t = \sqrt{ \frac{2 \times 700}{14} } \\ t = \sqrt{ \frac{700}{7} } \\ t = \sqrt{100} \\ t = 10 \: \:seconds$

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