Question

A metal ball of radius 2mm and density 10.5 is dropped in a water of coefficient of viscosity 9.8 and density 1.5 . find terminal velocity of ball
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Answer 1

➭ Question :-

$⟶$A metal ball of radius 2 mm and density 10.5 gm/cm³ is dropped in glycerin of coefficient of viscosity 9.8 poise and density 1.5gm/cm³. Find the terminal velocity of the ball .

➭ Given :-

$⟶$Radius = 2mm

$⟶$Density = 10.5gm/cm²

➭ To find :-

$⟶$the terminal Velocity of the ball

➭ Solution :-

From the formula of Terminal velocity,

$⟹ v = \frac{ {2gr}^{2}(t - σ) }{gη} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ ⟹\frac{2 \times 980 \times ( {0.2})^{2}(10.5 - 1.5) }{9 \times 9.8} cm/s \: \: \: \: \: \: \: \: \: \: \: \: \: \:\: \: \: \: \: \: \\ \\ ⟹ v = 8cm/s \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

Hence,the terminal Velocity of the ball is 8cm/s

Answer 2

Answer:

see attachment for explanation

Explanation:

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