Question

A metal ball of radius `r` is placed concentrically inside hollow metal sphere of inner radius `2r` and outer radius `3r`.The ball is given a charge `+2q` and the hollow sphere a total charge `-q` .The electrostatic potential energy of this system is

Answer 1

The electrostatic potential energy of this system is V = 7Q^2 / 24πϵ0 R

Explanation:

Radius =R=R

Inner radius =2R=2R

Outer radius =3R=3R

Charge =+2Q=+2Q

Hollow sphere a total charge = −Q

The electrostatic potential energy of this system=

By indication, inner wall of hollow sphere is induced with share −2.Q and its outer surface with charge.

Two conducting concentric, hollow sphere AA and BB have radii a and b respectively.

V =  1/4πϵ0   ×   Q/R

when, it is given that,

V^1 = 1 / 4  4πϵ0 x 2Q /2R  

V^11 =  1 /  4πϵ0 x Q /3R

V = Q / 4πϵ0 x (2Q / 2R + Q / 3R)

V = 1 / 4πϵ0 x 6 Q +2Q / 6R

V = 7Q^2 / 24πϵ0 R

Thus the electrostatic potential energy of this system is V = 7Q^2 / 24πϵ0 R

Also learn more

If atmospheric electric field is approximately 150 volt per metre and radius of the earth is 6400 kilometre then the total charge on the earth surface is​ ?

https://brainly.in/question/9673144

​