A metal ball strikes a steel plate at an angle (theta) with the vertical. If the coefficient of restitution is e, the angle at which the rebound will take place is
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A steel ball strikes a steel plate at an angle with the vertical . If the coefficient of restitution is e, the angle at which the rebound will take place is
9 years ago
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Consider the steel plate to be lying on the floor. Let the coefficient of friction between the plate and ball be n. Let the vertical component of velocity be y & horizontal component be x. Let time of collision be t(tending to zero). Final vertical component of velocity after collision is ey.
If average (normal) force during collision is F,
Ft = m ( y + ey) where m is mass of ball
Average frictional force ffriction = Fn = m (y + ey) n / t
So m (y + ey) n = m (x - xfinal)
xfinal = x - n (y + ey)
Let angle of rebound be a with vertical
tan a = ( x - n (y + ey) ) / ey = (tan b) / e - n/e - n where b is angle of striking of steel ball with the vertical
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The velocity in Y - direction will remain same since there is no external force
& velocity in X - direction =−eVx
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