a metal bar is 2m long.When 5.5 tonne is applied its length become 1.995m. find the compressive strain
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Answer:
metal bar 2m
tonne is applied 5.5
1.95mm28098
Answered by
1
Given:
Force (F) = 5.5 KN
Original length (L₁) = 2 m
Final Length (L₂) = 1.995 m
To find:
The compressive strain.
Solution:
Change in length (δl) = 2 m - 1.995 m
δl = 0.005 m
Compressive strain = Change in length / Original length
Compressive strain = δl / L₁
Compressive strain = 0.005 m / 2 m
Compressive strain = 0.0025
Therefore, the compressive strain is equal to 0.0025.
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