A metal block has a dimension of 40 cm into 20 cm into 15 cm the block is to be compressed so that the change in its volume is 0.1 cm cube the pressure is to be applied is in bracket k is equals to 5 into 10 to the power 10 newton per metre square
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mass of the wooden block = m= 5 kgdimensions = 40 cm × 20 cm × 10 cm
the weight of the wooden block applies a thrust on the table top.That is,Thrust = F = mg= 5 kg × 9.8 m/s²= 49 N
Area of a side = length × breadth
= 20 cm × 10 cm
= 200 cm²
= 0.02 m²
Pressure = thrust/ area
Pressure = 49 /0.02= 2450 N/m²
The same thrust in implied when it lies on the given dimension.
Area= length × breadth= 40 × 20= 800= 0.08 m²
Pressure = 49/0.08= 612.5
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