Question

) A metal block of dimension 10cm x 8cm x 5cm and having mass of 30Kg is dropped on the floor. Find the pressure exerted by it, if dropped on the (a) Largest face (b) Smallest face.​

Answer 1

Explanation:

Let P

1

,P

2

and P

3

be the pressures exerted by the brick while resting on different faces.

The dimensions of the given brick are 20cm×10cm×5cm

Case (i) : When the block is resting on 20cm×10cmface.

Thrust acting= Weight of the brick

T=500gwt

Area of constant (A)=20cm×10cm

Pressure exerted (P

1

)

=

Area

Thrust

=

20×10

500

∴P

1

=2.5gwtcm

−2

Case (ii) : When the block is resting on 20cm×5cmface

Thrust= Weight of the brick

=500gwt

Area of constant (A)=20cm×5cm

Pressure exerted

(P

2

)=

Area

Thrust

=

20×5

500

∴P

2

=5gwtcm

−2

Case (iii) : When the block on 10cm×5cmface

Thrust= Weight of the brick =500g.wt.

Area of contact =10cm×5cm

Pressure=

Area

Thrust

=

10×5

500

P

3

=10gwtcm

−2