a metal block of mass 0.5kg is placed on a surface inclined at an angle 30degrees if the coefficient of friction is 0.2, what force must be applied (1) to prevent it from sliding down the inclined plane, (2) to just move the block up the inclined plane and (3) to move it up the inclined plane with an acceleration of 20cm/s2 ?
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11th
Physics
Laws of Motion
Problems on Friction
A block of wood of mass 0.5...
PHYSICS
A block of wood of mass 0.5Kg is placed on plane making angle 30
∘
with the horizontal. If the coefficient of friction between the plane is 0.2, The force required to keep the body sliding down with uniform velocity is
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ANSWER
Given that,
Mass m=0.5 kg
Inclination θ=30
0
Coefficient of friction, μ=0.2
Velocity is constant, therefore acceleration is zero
We know that,
mgsinθ−μN+F=ma
mgsin30
o
−μmgcos30
o
+F=m×0
0.5×10×
2
1
−0.2×0.5×10×
2
3
+F=0
F=−1.633N
Hence, force is 1.6N(upward) parallel to incline plane.
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