Question

-
A metal block of mass 20 g is kept on a floor. The
contact area of metal block with the floor is 0.005
m2. The pressure exerted by the metal block on
the floor is (Take, g = 10 m/s2)​

Answer 1

Answer:

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Answer 2

Answer:

40 pascal

Explanation:

P = F/A

As, we have not been given 'force' we wil use the formula 'F=ma'

F = ma

F = 20g( change in kg) 0.020kg * 10

F = 0.2N

Now,

P = F/A

P = 0.2/0.005

P = 40Pa