Question

A metal block weighs 1.8N in air and 1.6N in water. What will be its weight in a liquid of a relative density of 0.6?

Answer 1

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A certain block weights 15N in air. It weighs 12N when immersed in water. When immersed in another liquid, it weighs 13N. The relative density of the block and the other liquid are respectively:

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Solution

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Correct option is A)

Upthrust acting on the block in water =15N−12N=3N = ( volume of solid immersed )( density of liquid ) g = V (1) 10 where V is the volume of the block , so V=

10

3

=0.3 cm

3

Block weighs 15N in air implies 15=mg , implies m=

10

15

=1.5g

now density =

volume

mass

=

0.3

1.5

= 5 g/cm

3

so density of block = 5 g/cm

3

hence , relative density of the block = density of block / density of water=

1

5

=5

now Upthrust acting on the block in the liquid =15N−13N=2N= (volume of solid immersed ) ( density of liquid ) g=Vρg=0.3( ρ)g ,

implies ρ of the liquid =

3

2

g/cm

3

so relative density of the liquid = density of liquid / density of water =

1

3

2

=

3

2

Explanation:

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