A metal carbonate “X” on reacting with an acid gives a gas which when passed through a solution “Y” gives the carbonate back. On the other hand , a gas “G” that is obtained during electrolysis of brine is passed on dry “Y” . It gives a compound “Z” , used for disinfecting drinking water. Identify X,Y,Z,G.
a. Sodium carbonate, antacid, oxygen , bleaching powder
b. Calcium Carbonate , lime water, chlorine, bleaching powder
c. Sodium Carbonate, vinegar , hydrogen , chlorine gas
d. Calcium Carbonate , lime water , nitrogen , chlorine gas
Answers
↘️ So, let's start reacting the chemical substances and form the compounds.
First of all, A metal carbonate on reacting with an acid, Carbon dioxide(Co2) is liberated. When, Carbon dioxide is passed over Slaked lime solution/Lime water, a precipitate is formed which is the earlier metal carbonate.
So, we can conclude that
Here, HCl is taken as optional acid by me. It is just to show the reaction that Co2 is liberated as a result.
Then, Carbon dioxide is passed over lime water/slaked lime solution.
On the other hand, an another elecryolytic recation is conducted. In which, Sodium chloride solution, popularly known as Brine solution is decomposed into Sodium and Chlorine gas.
This Chlorine gas is reacted with Lime water/ Slaked lime solution to form Calcium Oxychloride(Bleaching powder).
➤ Bleaching powder is used in disinfecting polluted water.
So, our final conclusion:
- Metal carbonate 'X' is Calcium carbonate used here.
- Solution 'Y' is slaked lime/Lime water solution.
- Gas 'G' obtained after the electrolysis of Brine solution is Chlorine gas.
- And, Compound 'Z' formed is Calcium Oxychloride/Bleaching powder.
Calcium carbonate, Lime water, Chlorine gas and Bleaching powder (Option B)
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