A METAL CARBONATE X ON REACTING WITH AN ACID GIVES A GAS WHICH WHEN PASSES THROUGH A SOLUTION Y GIVES THE CARBONATE BACK. ON THE OTHER HAND A GAS G THAT OBTAINED AT ANODE DURING ELECTROLYSIS OF BRINE IS PASSED ON DRY Y,
IIT GIVE A COMPOUND Z, USED FOR DISINFECTING DRINKING WATER. IDENTIFY X, Y, G AND Z.
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Answer:According to the problem:
Answer:According to the problem:Here,
X is calcium carbonate (CaCO3).
Y is slaked lime.
Z is bleaching powder (CaOCl2)
G is chlorine gas.
Hence the reactions are involved,
: Calcium carbonate gives carbon dioxide gas when reacts with hydrochloric acid.
: Calcium carbonate gives carbon dioxide gas when reacts with hydrochloric acid.CaCO3 + 2HCl ⇨ CaCl2 + CO2 + H2O
: Calcium carbonate gives carbon dioxide gas when reacts with hydrochloric acid.CaCO3 + 2HCl ⇨ CaCl2 + CO2 + H2O
: Calcium carbonate gives carbon dioxide gas when reacts with hydrochloric acid.CaCO3 + 2HCl ⇨ CaCl2 + CO2 + H2O Carbon dioxide turns lime water milky when passed through it because of formation of calcium carbonate. When carbon dioxide; so formed; is passed through lime water, lime water turns milky because of the formation of calcium carbonate.
: Calcium carbonate gives carbon dioxide gas when reacts with hydrochloric acid.CaCO3 + 2HCl ⇨ CaCl2 + CO2 + H2O Carbon dioxide turns lime water milky when passed through it because of formation of calcium carbonate. When carbon dioxide; so formed; is passed through lime water, lime water turns milky because of the formation of calcium carbonate.CO2 + Ca(OH)2 ⇨ CaCO3 + H2O
: Calcium carbonate gives carbon dioxide gas when reacts with hydrochloric acid.CaCO3 + 2HCl ⇨ CaCl2 + CO2 + H2O Carbon dioxide turns lime water milky when passed through it because of formation of calcium carbonate. When carbon dioxide; so formed; is passed through lime water, lime water turns milky because of the formation of calcium carbonate.CO2 + Ca(OH)2 ⇨ CaCO3 + H2OOn the electrolysis of brine, chlorine gas is deposited over anode which gives calcium oxychloride (Bleaching powder) on passing over slaked lime. The bleaching powder is used in disinfecting the drinking water.
: Calcium carbonate gives carbon dioxide gas when reacts with hydrochloric acid.CaCO3 + 2HCl ⇨ CaCl2 + CO2 + H2O Carbon dioxide turns lime water milky when passed through it because of formation of calcium carbonate. When carbon dioxide; so formed; is passed through lime water, lime water turns milky because of the formation of calcium carbonate.CO2 + Ca(OH)2 ⇨ CaCO3 + H2OOn the electrolysis of brine, chlorine gas is deposited over anode which gives calcium oxychloride (Bleaching powder) on passing over slaked lime. The bleaching powder is used in disinfecting the drinking water.Ca(OH)2 + Cl2 ⇨ CaOCl2 + H2O
: Calcium carbonate gives carbon dioxide gas when reacts with hydrochloric acid.CaCO3 + 2HCl ⇨ CaCl2 + CO2 + H2O Carbon dioxide turns lime water milky when passed through it because of formation of calcium carbonate. When carbon dioxide; so formed; is passed through lime water, lime water turns milky because of the formation of calcium carbonate.CO2 + Ca(OH)2 ⇨ CaCO3 + H2OOn the electrolysis of brine, chlorine gas is deposited over anode which gives calcium oxychloride (Bleaching powder) on passing over slaked lime. The bleaching powder is used in disinfecting the drinking water.Ca(OH)2 + Cl2 ⇨ CaOCl2 + H2OBleaching powder is used for disinfecting drinking water.
Therefore;
Therefore;Metal carbonate ‘X’ is calcium carbonate.
Therefore;Metal carbonate ‘X’ is calcium carbonate.Solution ‘Y’ is lime water (Calcium hydroxide).
Therefore;Metal carbonate ‘X’ is calcium carbonate.Solution ‘Y’ is lime water (Calcium hydroxide).Gas ‘G’ is chlorine gas.
Therefore;Metal carbonate ‘X’ is calcium carbonate.Solution ‘Y’ is lime water (Calcium hydroxide).Gas ‘G’ is chlorine gas.Dry ‘Y’ is dry calcium hydroxide (dry slaked lime).
Therefore;Metal carbonate ‘X’ is calcium carbonate.Solution ‘Y’ is lime water (Calcium hydroxide).Gas ‘G’ is chlorine gas.Dry ‘Y’ is dry calcium hydroxide (dry slaked lime).Compound ‘Z’ is bleaching powder (Calcium oxychloride).
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