a metal container is in the form of a cylinder surmounted by a hemisphere of the same eadius. the internal height of the cylinder is 3.5 m.calculate the total surface area of the container
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alishaagra99:
value of pi here is 3.14
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let the radius = r
C.S.A of the cylinder mounted = 2Πrh
C.S.A of the hemisphere = 2Π r²
T.S.A of Figure = C.S.A of Cylinder + hemisphere
T.S.A of the figure formed = 2 Π r ( h + r )
T.S.A= 6.28 r( 3.5 + r) m²
if the cylinder is covered by a lid
Then T.S.A = 2Πr² +Πr² + 2Πrh
T.S.A = 3.14r( 2r + r + 2h )
T.S.A =3.14 r (2r + r+ 7) m²
C.S.A of the cylinder mounted = 2Πrh
C.S.A of the hemisphere = 2Π r²
T.S.A of Figure = C.S.A of Cylinder + hemisphere
T.S.A of the figure formed = 2 Π r ( h + r )
T.S.A= 6.28 r( 3.5 + r) m²
if the cylinder is covered by a lid
Then T.S.A = 2Πr² +Πr² + 2Πrh
T.S.A = 3.14r( 2r + r + 2h )
T.S.A =3.14 r (2r + r+ 7) m²
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