Question

A metal contains two oxides. One contains 46.7% of the metal and the other oxide contains 63.94% of the metal. Show that these results follow the law of multiple proportions​

Answer 1

Answer:

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Explanation:

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Answer 2

Oxide 1 = M:O = 53.33 :46.67 = 1:0.8 = 1:1

Oxide 2= M:O = 36.06:63.94 = 1: 1.77 = 1:2

so the oxygen is in ratio of 1:2 so this is a example of multiple proportion..