a metal crystallizes crystallizes in a face centred cubic structure if the edge length of its unit cell is the closest approach between two atoms in metallic crystal will be???
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☬ YOUR ANSWER ☬
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⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣
For acc. arrangement , 4r = √2a
where, r = radius and a = edge length
•°• Closet distance = 2R = √2A/A =
BY rationalizing ,
= a/√2
⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡
╒══════════════════════╕
☬ THANKS! @Brainlyconquerer ☬
╘══════════════════════╛
☬ YOUR ANSWER ☬
╘═════════════════════╛
⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣
For acc. arrangement , 4r = √2a
where, r = radius and a = edge length
•°• Closet distance = 2R = √2A/A =
BY rationalizing ,
= a/√2
⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡
╒══════════════════════╕
☬ THANKS! @Brainlyconquerer ☬
╘══════════════════════╛
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As we learnt in
Relation between radius of constituent particle, r and edge length, a for face centered cubic unit cell -
a/√2
The closest approach b/w two atoms
pLz pLz mArK mY AnSwER aS BrAinLiESt
_______________________________#PB
Relation between radius of constituent particle, r and edge length, a for face centered cubic unit cell -
a/√2
The closest approach b/w two atoms
pLz pLz mArK mY AnSwER aS BrAinLiESt
_______________________________#PB
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