A metal crystallizes in a body centred cubic structure . if 'a' is the edge length of its unit cell , 'r' is the radius of th sphere . what is the relationship b/w 'r' nd 'a'
Answers
Answer:
The relationship between 'r' and 'a' is 'r' = (√2/8)a.
Explanation:
From the above question,
They have given :
The body centred cubic (BCC) structure is a type of crystal structure where each unit cell is composed of 8 atoms located at the corners of a cube, and one atom located at the center of the cube.
A body centred cubic (BCC) structure is a type of crystal structure where each unit cell is composed of 8 atoms located at the corners of a cube, and one atom located at the center of the cube.
The edge length of a BCC unit cell is represented by a.
The radius of a sphere is represented by r.
The relationship between 'r' and 'a' is given by:
r = (√2/8)a.
The edge length of a BCC unit cell is represented by a. The radius of a sphere is represented by r. The relationship between 'r' and 'a' can be found by using the following equation: r = (√2/8)a. This equation shows that the radius of the sphere is directly proportional to the edge length of the unit cell.
For more such related questions : https://brainly.in/question/6815594
#SPJ3