a metal cube is melted to form for new smaller cubes of equal volume what is the ratio of the total surface area of the original cube to that of one of the smaller cubes
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Step-by-step explanation:
given -vol of big cube =vol of small cubes
formula for volume of cube=a×a×a
where a is side of cube
formula for surface area =6×a
the bigger cube is made into n number of smaller cubes so
vol of n number of smaller cubes=n×a×a×a
surface area=n×6×a'
so the ratio of surface area =6a/n6a'
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