a metal cube is melted to form four new smaller cubes of equal volume what is the ratio of the total surface area of the original cube to that of one of the smaller cube
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Answer:
(∛4)² : 1
Step-by-step explanation:
Let the side of the smaller cube=a and larger cube=b
Volume of big cube=Volume of all small cubes combined
b³=4a3
b³/a³=4
b/a=∛4
b²/a²=(∛4)² (squaring both sides)
6b²/6a²=(∛4)²
Ratio= (∛4)² : 1
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