a metal cube is melted to form three smaller cubes of edges 3 cm , 4 cm and 5 cm .Find the edge of the original metal cube.
Answers
Answered by
49
vol. of larger metal cube = vol. of three smaller cubes
=(3)³ + 4³ + 5³
= 27 + 64 + 125
= 216 cm³
vol.of larger metal cube = 216 cm³
(a)³ = 216 cm³
a³ = 6³
a = 6 cm
therefore edge of larger metal cube is 6 cm
=(3)³ + 4³ + 5³
= 27 + 64 + 125
= 216 cm³
vol.of larger metal cube = 216 cm³
(a)³ = 216 cm³
a³ = 6³
a = 6 cm
therefore edge of larger metal cube is 6 cm
Answered by
15
side1=3 side2=4 side3=5cm
volume of all cubes =a3
volume of cube 1 = (3)(3)(3)=27
""" """ "" 2=(4)(4)(4)=64
""" """ """" " 3=(5)(5)(5)=125
volume of larger cube= 27+64+125=216cm3
216=a3
6cm =a
volume of all cubes =a3
volume of cube 1 = (3)(3)(3)=27
""" """ "" 2=(4)(4)(4)=64
""" """ """" " 3=(5)(5)(5)=125
volume of larger cube= 27+64+125=216cm3
216=a3
6cm =a
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