Question

A metal cube of 5 cm edge and density 9 g cm-3 is suspended by a thread so as to be completely immersed in a liquid of density 1.2 g cm-3. Find the tension in the thread. (Take g = 10 ms-2).

Answer 1

Answer:

Side of the cube =5 cm

So, its volume , V=a

3

=125 cm

3

Mass of cube =V×d=125×9=1125 g

Weight =mg=1125×1000=1125000 dyne

Now, cube is immersed is liquid,

∴ buoynat force =Vρg=125×1.2×1000=150000 dyne

So, Tension = apparent weight =(1125000−150000) dyne=975000 dyne=9.75 N

Explanation:

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