a metal cube of edge 12cm is melted and formed into three smaller cubes. if the edge of two smaller cubes are 6cm and 8cm, the edge of the third smaller cube is
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15
Given,
Edge(side)=12cm
Volume =side^3
=》 12×12×12
Melted into 3 cubes of volume
cude with side 6cm
=6×6×6
cube with side8cm
=8x8x8
let the side be x
then
(8x8x8)+(6×6×6)+(x×x×x)=12×12×12
=》x^3=(12×12×12)-728
=》x^3=1728-728
=》x^3=1000
=》x=10
shreyarawat46:
thanks
Answered by
10
volume of cube is a^3
so, volume with side 12 cm is 12^3 = 1728
volume of cube with sides 6 cm is 6^3 =216
similarly for 8 cm is = 8^3 = 512
volume of third cube = 1728 - (216 +512) =1000
now ,a^3 = 1000
therefore a = 10 cm answer
so, volume with side 12 cm is 12^3 = 1728
volume of cube with sides 6 cm is 6^3 =216
similarly for 8 cm is = 8^3 = 512
volume of third cube = 1728 - (216 +512) =1000
now ,a^3 = 1000
therefore a = 10 cm answer
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