A metal Cube of edge 12cm is melted and formed into three smaller cubes.If the edges of the two smaller cubes are 6cm and 8cm,find the edge of the third smaller cube?
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volume of the larger cube=12×12×12
=1728
volume of the smaller cubes are 6×6×6 +8×8×8= 216 +512
=728
therefore 1728-728
=1000
volume of the other smaller cube is 1000
therefore the edge of the cube is 10 cm
=1728
volume of the smaller cubes are 6×6×6 +8×8×8= 216 +512
=728
therefore 1728-728
=1000
volume of the other smaller cube is 1000
therefore the edge of the cube is 10 cm
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