A metal cube of edge 5cm and density 9.0g/cm³ is suspended by a thread so as to be completely immersed in a liquid of density 1.2g/cm³. Find the tension in thread.
Answers
Volume of metal cube = (5 cm)^3 = 125 x 10^−6 m^3.
Density of metal = 9 g/cm3 = 9000 kg/m^3.
Mass of the metal cube m = volume x density
= 125 x 10^−6 m^3 x 9000 kg/m^3.
= 1.125 kg
Weight of the metal cube in air = mg = 1.125 kg x 10 ms^-2 = 11.25 N
Volume of liquid displaced = Volume of metal cube = 125 x 10^−6 m^3.
Mass of liquid displaced = Volume x density of liquid
= 125 x 10^−6 m^3.1200 kg/m^3.
= 0.15 kg
Weight of liquid displaced = 0.15 kg x 10 m/s^2 = 1.5 N = upthrust
Weight of metal cube in liquid = Weight of the metal cube in air - upthrust
= 11.25 − 1.5
= 9.75 N
Therefore tension in the string = 9.75 N.
Answer:
Explanation:
Mass of the metal cube m = volume x density = 125 x 10^−6 m^3 x 9000 kg/m^3. = 1.125 kg
Weight of the metal cube in air = mg = 1.125 kg x 10 ms^-2 = 11.25 N
Volume of liquid displaced = Volume of metal cube = 125 x 10^−6 m^3.
Mass of liquid displaced = Volume x density of liquid
= 125 x 10^−6 m^3.1200 kg/m^3.
= 0.15 kg
Weight of liquid displaced = 0.15 kg x 10 m/s^2 = 1.5 N = upthrust