A metal cube of edge 5cm and density 9.0gcm^-3 is suspended by a thread so as to be completely immersed in a liquid of density 1.2gcm^-3. find the tension in thread. ( take g=10ms^-2)
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Answered by
2
Answer
Side of the cube = 5 cm
So, its volume, V = a = 125 cm3
Mass of cube = V x d = 125 x 9 = =
1125 g
Weight = mg = 1125 x 1000 =
1125000 dyne
Now, cube is immersed is liquid,
..buoynat force = V pg = 125 x 1.2 x
1000 = 150000 dyne
So, Tension = apparent weight =
(1125000 – 150000) dyne =
975000 dyne = 9.75 N
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Answered by
7
Answer:
Answer
Side of the cube = 5 cm
So, its volume, V = a = 125 cm3
Mass of cube = V x d = 125 x 9 = =
1125 g
Weight = mg = 1125 x 1000 =
1125000 dyne
Now, cube is immersed is liquid,
..buoynat force = V pg = 125 x 1.2 x
1000 = 150000 dyne
So, Tension = apparent weight =
(1125000 – 150000) dyne =
975000 dyne = 9.75 N
Explanation:
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