Question

a metal cube of length 0.1 metre is charged by a 12 mew C. calculate its surface charge density​

Answer 1

$surface \: charge \: density \: = \frac{q}{a} \\ \\ = \frac{12 \times {10}^{ - 6} }{6 \times ({0.1)}^{2} } \\ \\ = 2 \times \frac{ {10}^{ - 6} }{ {10}^{ - 2} } \\ \\ = 2\times {10}^{ - 4} coul.{m}^{ - 2}$

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Answer 2

Answer:

Surface Charge Density = 2 × 10^-4 C/m²

Explanation:

Given,

Charge = 12 × 10^-6 C

Length = 0.1 m

By using the formula of total surface area of cube.

TSA of cube = 6 × (length)²

.°. TSA of cube = 6l²

Putting the values of 'l' in the equation.

TSA of cube = 6l²

TSA of cube = 6 × (0.1)²

TSA of cube = 6 × 10^-2 m²

Now,

By using the formula of surface charge density.

Surface Charge Density = Q/A

Surface Charge Density = 12 × 10^-6/6 × (0.1)²

Surface Charge Density = 2 × 10^-6/10^-2

Surface Charge Density = 2 × 10^-4 C/m²