Question

A metal cube of length 10.0 mm at 0°C (273K) is heated to
200°C (473K). Given : its coefficient of linear expansion is
2 × 10⁻⁵ K⁻¹. The percent change of its volume is
(a) 0.1 (b) 0.2
(c) 0.4 (d) 1.2

Answer 1

Answer:

Here percentage change in volume is given as, ΔV=γ×t×100

where, γ=3α

So, ΔV=3α×(T1−T2)×100

ΔV=3×2×10−5×(473−273)×100=1.2(Option d)

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